4/x^2+3x-10-1/x^2+x-6=3/x^2-x-12

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Solution for 4/x^2+3x-10-1/x^2+x-6=3/x^2-x-12 equation: 



4/x^2+3x-10-1/x^2+x-6=3/x^2-x-12

We move all terms to the left:

4/x^2+3x-10-1/x^2+x-6-(3/x^2-x-12)=0



Domain of the equation: x^2!=0

x^2!=0/

x^2!=√0

x!=0

x∈R





Domain of the equation: x^2-x-12)!=0

x∈R



We add all the numbers together, and all the variables

4x+4/x^2-1/x^2-(3/x^2-x-12)-16=0

We get rid of parentheses

4x+4/x^2-1/x^2-3/x^2+x+12-16=0

We multiply all the terms by the denominator


4x*x^2+x*x^2+12*x^2-16*x^2+4-1-3=0

We add all the numbers together, and all the variables

-4x^2+4x*x^2+x*x^2=0

Wy multiply elements

-4x^2+4x^3+x^3=0

We do not support expression: x^3

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